3(n-1)=2^n-1

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Solution for 3(n-1)=2^n-1 equation: 



3(n-1)=2^n-1

We move all terms to the left:

3(n-1)-(2^n-1)=0

We multiply parentheses

3n-(2^n-1)-3=0

We get rid of parentheses

3n-2^n+1-3=0

We add all the numbers together, and all the variables

3n-2^n-2=0

We move all terms containing n to the left, all other terms to the right

3n-2^n=2

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